diff --git a/searchsploit.py b/searchsploit.py
index 22d9dd9..4a96268 100755
--- a/searchsploit.py
+++ b/searchsploit.py
@@ -2,6 +2,7 @@
 from sys import argv, exit
 import os
 import argparse
+import re
 
 # Default options
 COL = 0
@@ -209,7 +210,7 @@ def drawline(lim):
     print(line)
 
 
-def highlightTerm(line, term):
+def highlightTerm(line: str, term)->str:
     """ Part one of new highlighting process. Highlights by adding :8 and :9 as escape characters as ansi takes several lines. the rest is compiled in separater unless autocomp is true\n
     @line: the phrase to be checked\n
     @term: the term that will be found in line and used to highlight the line\n
@@ -219,6 +220,10 @@ def highlightTerm(line, term):
     if not parseArgs.colour:
         return line
 
+    # Adjustments for if term is version tuple
+    if type(term) is tuple:
+        term = term[1] # TODO: Make way to highlight line if fits version parameters
+
     marker = 0  # marks where the term is first found
     term = term.lower()
 
@@ -309,6 +314,41 @@ def findExploit(id):
         else:
             return i, exploit
 
+baseVersion = re.compile(r'((?:(?:<)\s*)|(?:[RrVv]))?((?:\d+(?:\.(?:\d+|x))+)|(?:\d+))')
+
+def hasVersion(term: str)->bool:
+    """ Returns true if the string contains any numbers that could resemble a verison
+    """
+    return (len(baseVersion.findall(term)) > 0)
+
+def getVersion(term: str):
+    return baseVersion.findall(term) # returns the first found object, taking tuple out of list
+
+def cmpVersion(leftVersion: str, rightVersion: str)->int:
+    """ Compares the two versions and returns an integer depending on which one if newer
+    """
+    leftComponent = leftVersion.split(".")
+    rightComponent = rightVersion.split(".")
+    for i in range(min(len(leftComponent), len(rightComponent))):
+        if (leftComponent[i] != rightComponent[i]):
+            # Dealing with wildcard scenarios
+            if ("x" in leftComponent[i]):
+                if (len(re.findall("((?:{0})|(?:{1}))$".format(leftComponent[i],leftComponent[i].replace("x","\\d*")), rightComponent[i])) > 0):
+                    # if the string matches itself or regex replacing all x's with \d's, then it is a match
+                    return 0
+            elif ("x" in rightComponent[i]):
+                if (len(re.findall("((?:{0})|(?:{1}))$".format(rightComponent[i],rightComponent[i].replace("x","\\d*")), leftComponent[i])) > 0):
+                    # if the string matches itself or regex replacing all x's with \d's, then it is a match
+                    return 0
+
+            # Removing excess chars
+            # print(leftComponent[i], rightComponent[i])
+            for j in re.findall("([A-Za-z]+)", leftComponent[i]):
+                leftComponent[i] = leftComponent[i].replace(j, "")
+            for j in re.findall("([A-Za-z]+)", rightComponent[i]):
+                rightComponent[i] = rightComponent[i].replace(j, "")
+            return int(rightComponent[i]) - int(leftComponent[i])
+    return len(rightComponent) - len(leftComponent) # if they are equal up their shortest version, then the latest is the longest version
 
 def validTerm(argsList):
     """ Takes the terms inputed and returns an organized list with no repeats and no poor word choices
@@ -343,6 +383,11 @@ def validTerm(argsList):
         print("if you want to search with them anyway, run the command again with the -i arguement")
         exit()
 
+    # Converting certain terms into version terms
+    for i in range(len(argsList)):
+        if hasVersion(argsList[i]):
+            argsList[i] = getVersion(argsList[i])[0] # Getting first result from list
+
     return argsList
 
 
@@ -366,25 +411,50 @@ def searchdb(path="", terms=[], cols=[], lim=-1):
     db = dbFile.read().split('\n')
     for lines in db:
         if (lines != ""):
-            for ex in parseArgs.exclude:
+            for ex in parseArgs.exclude: # Removing positive lines with excluded values
                 if parseArgs.case and ex in lines:
                     break
                 elif ex in lines.lower():
                     break
             else:
                 for term in terms:
-                    if parseArgs.title:
-                        line = lines.split(",")[2]
-                        if parseArgs.case:
-                            if term not in line:
+                    if type(term) is str: # separate versions from search terms
+                        if parseArgs.title:
+                            line = lines.split(",")[2]
+                            if parseArgs.case:
+                                if term not in line:
+                                    break
+                            elif term not in line.lower():
                                 break
-                        elif term not in line.lower():
-                            break
-                    elif parseArgs.case:
-                        if term not in lines:
+                        elif parseArgs.case:
+                            if term not in lines:
+                                break
+                        elif term not in lines.lower():
                             break
-                    elif term not in lines.lower():
-                        break
+                    elif type(term) is tuple:
+                        line = lines.split(",")[2]
+                        versions = getVersion(line)
+                        versionCompatible = False # helps for the or status here
+                        if (len(versions) == 0):
+                            break # if no versions could be detected in line, throw out line
+                        if (term[0] != "") and "<" not in term[0]: # version has r or s in front
+                            for v in versions:
+                                if (v[0].lower() != term[0]):
+                                    continue # skip this if version doesnt start with same tag
+                                versionCompatible = versionCompatible or (cmpVersion(term[1], v[1]) >= 0)
+                                # this will only ever be true if just one is true
+                            if not versionCompatible:
+                                break
+                        elif "<" in term[0]:
+                            for v in versions:
+                                versionCompatible = versionCompatible or (cmpVersion(term[1], v[1]) <= 0)
+                            if not versionCompatible:
+                                break
+                        else:
+                            for v in versions:
+                                versionCompatible = versionCompatible or (cmpVersion(term[1], v[1]) >= 0)
+                            if not versionCompatible:
+                                break
                 else:
                     for i in cols:
                         space = lines.split(",")