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ObservableInput<T> should support Thennable<T>, not PromiseLike<T> #7437

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@benlesh

The type on ObservableInput is probably too strict.

We'll want to support Thennable<T> instead, as that's all that is required to convert with from et al.

interface Thennable<T> {
  then(onresolved?: ((value: T) => void) | null | undefined, onrejected?: ((reason: any) => void) | null | undefined): void;
}

The upside is we can then support more. The downside is if we decide we need to rely on the returned value of the then function, It'll require a breaking change.

Implementor note: We probably don't want to publicly expose Thennable, I'm sure a lot of folks already have that implemented in their codebase. It's been a mistake that we export * from types, honestly.

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  1. HirparaSEdit commented on Feb 3, 2024

    @HirparaSEdit

    // Define the Thennable interface
    interface Thennable {
    then(onresolved?: ((value: T) => void) | null | undefined, onrejected?: ((reason: any) => void) | null | undefined): void;
    }

    // Function that takes an ObservableInput
    function processObservable(observable: Thennable) {
    // Simulate processing the observable
    observable.then(
    (value) => {
    console.log("Resolved:", value);
    },
    (reason) => {
    console.error("Rejected:", reason);
    }
    );
    }

    // Example usage
    const myObservable: Thennable = {
    then: (onresolved, onrejected) => {
    // Simulate resolving the observable after a delay
    setTimeout(() => {
    if (Math.random() < 0.5) {
    onresolved?.("Success");
    } else {
    onrejected?.("Failure");
    }
    }, 1000);
    },
    };

    // Process the observable
    processObservable(myObservable);

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