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When a lambda is using in-line presentation, then -> is like a binary
operator.
When a lambda is using block presentation, then the (params) -> { part
ought to bind more tightly together than we see here.
Activity
cushon commentedon May 15, 2015
I think that breaking before
->is a bug. Fixing that would make it a little better:kevinb9n commentedon May 15, 2015
Roughly, I would say:
When a lambda is using in-line presentation, then -> is like a binary
operator.
When a lambda is using block presentation, then the
(params) -> {partought to bind more tightly together than we see here.
On Fri, May 15, 2015 at 8:47 AM, Liam Miller-Cushon <
notifications@github.com> wrote:
Kevin Bourrillion | Java Librarian | Google, Inc. | kevinb@google.com
Merge pull request #2 from MrDolch/update-from-template