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Array<number>.sort() uses lexicographic comparator by default #32593
Description
TypeScript Version: 3.4.0-dev.201xxxxx
Search Terms:
typed arrays
default comparator
lexicographic comparator
numeric comparator
Code
let a: Array<number> = [12,4];
a.sort();
console.log(a);Expected behavior:
[4, 12]
Actual behavior:
[12, 4]
Playground Link:
https://codepen.io/greddyatpt/pen/aepoaN?editors=1111
Related Issues:
#18286 is related but it recommends a breaking change. Instead, the default comparator should take the element type into consideration.
Activity
MartinJohns commentedon Jul 28, 2019
This is unrelated to TypeScript, it's up to the runtime.
Also this is the correct behavior: MDN documentation of Array.prototype.sort()
Changing this would violate several of the TypeScript Design Goals:
RyanCavanaugh commentedon Jul 29, 2019
TypeScript doesn't change the behavior of JavaScript code.
Rudxain commentedon Nov 12, 2024