Is it possible for a function to return a list of values? #3418

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1. zhongsp commented on Jun 8, 2015

   

   Patrick Zhong (zhongsp)

   on Jun 8, 2015

   Contributor

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   Maybe you could use tuple types:

   function x(): [number, string, number] {
       return [1, 'dsdsq', 45678.45];
   }
   
   var tuple: [number, string, number] = x(),
       t0 = tuple[0],
       t1 = tuple[1],
       t2 = tuple[2];
2. kitsonk commented on Jun 8, 2015

   

   Kitson Kelly (kitsonk)

   on Jun 8, 2015

   Contributor

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   Largely I assume it isn't present in TypeScript, because it isn't present in JavaScript/EcmaScript and the intent of TypeScript is not to "break" JavaScript, but be able to emit valid JavaScript, which would be hard to do.

   As a way of solving this in a "JavaScript way", ES6 is adding array destructuring assignment and TypeScript allows you to utilise this feature now.

   function x() {
       return [ 1, 'dsdsq', 45678.45 ];
   }
   
   let [a, b, c] = x(); /* a = 1, b = 'dsdsq', c = 45678.45 */

   TypeScript allows you to destructure arrays, even when targeting non-ES6.
3. Ryan Cavanaugh (RyanCavanaugh)

   added

   By DesignDeprecated - use "Working as Intended" or "Design Limitation" insteadDeprecated - use "Working as Intended" or "Design Limitation" instead

   on Jun 8, 2015
4. RyanCavanaugh commented on Jun 8, 2015

   

   Ryan Cavanaugh (RyanCavanaugh)

   on Jun 8, 2015

   Member

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   If you combine the comments so far, you'll end up at an ideal solution:

   function x(): [number, string, number] {
       return [ 1, 'dsdsq', 45678.45 ];
   }
   
   // a: number, b: string, c: number
   let [a, b, c] = x(); /* a = 1, b = 'dsdsq', c = 45678.45 */

   We can't change the existing JS syntax since the comma operator already has a different meaning here.
5. Ryan Cavanaugh (RyanCavanaugh)

   closed this as completedon Jun 8, 2015
6. Vadorequest commented on Jun 8, 2015

   

   Vadorequest (Vadorequest)

   on Jun 8, 2015

   Author

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   Thanks!
   Le 8 juin 2015 18:32, "Ryan Cavanaugh" notifications@github.com a écrit :

   If you combine the comments so far, you'll end up at an ideal solution:

   function x(): [number, string, number] {
   return [ 1, 'dsdsq', 45678.45 ];
   }
   // a: number, b: string, c: number
   let [a, b, c] = x(); /* a = 1, b = 'dsdsq', c = 45678.45 */

   We can't change the existing JS syntax since the comma operator already
   has a different meaning here.

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